2k^2-k-8=0

Solution for 2k^2-k-8=0 equation:

2k^2-k-8=0

We add all the numbers together, and all the variables

2k^2-1k-8=0

a = 2; b = -1; c = -8;
Δ = b2-4ac
Δ = -12-4·2·(-8)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{65}}{2*2}=\frac{1-\sqrt{65}}{4}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{65}}{2*2}=\frac{1+\sqrt{65}}{4}
$